Let F be the event that a customer is dissatisfied with the food at a restaurant and let S be the event that a customer is dissatisfied with the service. If P(F) = .15, P(S) = .40, and P(F ∩ S) = .10, what is the probability that a customer is dissatisfied with either the service or the food? a. .65 b. .55 c. .45 d. .10

Answer:0.45, option cStep-by-step explanation:Probability that a customer is dissatisfied with customer service P(S) is 0.40Probability that a customer is dissatisfied with food P(F) is 0.15Probability he is dissatisfied with both food and customer service P(FnS)  is 0.10probability he is dissatisfied with either food or customer service is given by [tex]P(FuS) = P(F) +P(S) - P(FnS)[/tex] [tex]=0.15+0.40-0.10 \\=0.45[/tex]the probability that a customer is dissatisfied with either the service or the food is 0.45