Mr. Howard is a student teacher at the local junior high. His first‐period class of 40 students averaged 96% on a recent test. His second‐period class of 20 students averaged 90% on the same test. What was the combined average for both classes?

Answer: The combined average is 94%Step-by-step explanation:for first period, number of students =40average =96%for second period, no of students =20average =90%but [tex]average = \frac{sum of scores}{no of students}[/tex] let [tex]S_1[/tex] =sum of students for the first period     [tex]S_2[/tex] =sum of students for the second periodfor first period;[tex]\frac{S_{1} }{40} =96%[/tex][tex]S_{1}= 96*40=3840[/tex]for second period,[tex]\frac{S_{2} }{20} =90%[/tex][tex]S_{1}= 90*20=1800[/tex]therefore the combined average = [tex]\frac{S_1+S_2}{40+20}[/tex]that is [tex]\frac{3840+1800}{40+20}[/tex] [tex]= 94%[/tex]so combined average is 94%